SOLUTION: This is what I have for this problem but I cannot figure out (A′ U C′) ∩ B ′. Can someone please help me!!!!!!! Thank you!!!!!!
6. (3 pts) Given U = {l
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Question 198077: This is what I have for this problem but I cannot figure out (A′ U C′) ∩ B ′. Can someone please help me!!!!!!! Thank you!!!!!!
6. (3 pts) Given U = {l, m, n, o, p, q, r, s, t, u, v, w}, A = {l, o, p, q, s, t}, B = {n, o, r, s, v, w},
and C = {l, m, n, q, r, t}, find (A′ U C′) ∩ B ′.
A', list the elements of U that are NOT in A.
A’ = {m, n, r, u, v, w}
B', list the elements of U that are NOT in B.
B’ = {l, m, p, q, t, u}
B’, list the elements of U that are NOT in C.
C’ = {o, p, s, u, v, w}
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
figure out (A′ U C′) ∩ B ′. Can someone please help me!!!!!!! Thank you!!!!!!
6. (3 pts) Given U = {l, m, n, o, p, q, r, s, t, u, v, w}, A = {l, o, p, q, s, t}, B = {n, o, r, s, v, w},
and C = {l, m, n, q, r, t}, find (A′ U C′) ∩ B ′.
A', list the elements of U that are NOT in A.
A’ = {m, n, r, u, v, w}
B', list the elements of U that are NOT in B.
B’ = {l, m, p, q, t, u}
C’, list the elements of U that are NOT in C.
C’ = {o, p, s, u, v, w}
--------------------------------------------
(A′ U C′) = {m,n,r,u,v,w,o,p,s)
-----------------------------------
(A′ U C′) ∩ B′ = {m,p,u)
========================================
Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You're off to a great start. Now simply combine the sets A' and C' to perform the set union A' U C'. So take ALL the elements in sets A' and C' and combine them to make a new set (remember to take out duplicates). So after combining the two sets, we get:
Now the next step is to perform an intersection with the sets
and
. So what elements do
and
have in common? In other words, what are the common elements between the sets
and
? Since these sets only have the elements "m","p",and "u" in common, this means that
Let me know if this makes sense.
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