# SOLUTION: at a restaurant, the bill for two coffees and 3 hot chocolates as 10.95. At another table the bill for one coffee and 2 hot chocolates was 6.65. How much did each type of beverage

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 Question 19575: at a restaurant, the bill for two coffees and 3 hot chocolates as 10.95. At another table the bill for one coffee and 2 hot chocolates was 6.65. How much did each type of beverage cost? I really appreciate your help. I don't even know where to begin.Answer by mmm4444bot(95)   (Show Source): You can put this solution on YOUR website!Hello There: Begin by assigning variable names for the two unknown amounts. x = the price of a coffee y = the price of a hot chocolate From the given information, 2 coffees and 3 hot chocolates totaled \$10.95. This alows us to write an equation: 2*x + 3*y = 10.95 Likewise, the other information leads to: x + 2*y = 6.65 Solve the second equation for x: x = 6.65 - 2*y Substitute this expression for x in the first equation: 2*(6.65 - 2*y) + 3*y = 10.95 Can you now solve this equation for y? Once you know the value of y, you can find x because: x = 6.65 - 2*y ~ Mark