SOLUTION: A chemist needs 16 liters of a 15% solution. She has two saline solutions with strengths 12% and 20%. Find the amount of 12% solution and the amount of 20% solutioin she should ad

Question 192321: A chemist needs 16 liters of a 15% solution. She has two saline solutions with strengths 12% and 20%. Find the amount of 12% solution and the amount of 20% solutioin she should add to get 1 liters of a 15% solution.
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
.20x+.12(1-x)=.15*1
.20x+.12-.12x=.15
.08x=.15-.12
.08x=.03
x=.03/.08
x=.375 liters od 20% solution is used.
1-.375=.625 liters of 12% solution is also used.
Proof:
.20*.375+.12*.625=.15*1
.075+.075=.15
.15=.15
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