SOLUTION: My question is: If you have 60 grams of a solution that is 32% sugar, how much sugar do you add to make it 50% sugar. I found this question and tried to go by it (my answers ar

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: My question is: If you have 60 grams of a solution that is 32% sugar, how much sugar do you add to make it 50% sugar. I found this question and tried to go by it (my answers ar      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   


Question 19005: My question is: If you have 60 grams of a solution that is 32% sugar, how much sugar do you add to make it 50% sugar.
I found this question and tried to go by it (my answers are second) and came up with a negative number so I know I am wrong. Please help!
Question 16433: A chemist has 2.5 liters of a solution which is 70% acid. How much water should be added to obtain a 50% acid solution?
Answer by venugopalramana(287) (Show Source):
chemist has 2.5 60 grams liters of a solution which is 70% 32 acid. How much water sugar should be added to obtain a 50% 50% acid solution?
qty.of solution = 2.5 l 60g
% acid in solution = 70 32
hence qty.of acid in the solution = 2.5*70/100 = 1.75 l (60*32/100= 19.2)
required percentage = 50 50
let the water to be added = x l xG
total qty.of solution = (2.5+x) l (60+x)G
qty of acid = same as before = 1.75 l 19.2 G
% acid in the new solution = 1.75*100/(2.5+x) = 50 as given 19.2*100/(60+x)=50
175= 50(2.5+x) 1920 = 50(60+x)
2.5+x = 175/50 = 3.5 60+x = 1920/50 = 38.4
x= 3.5 - 2.5 = 1 litre x = 38.4 -60 x=-21.6

Answer by Earlsdon(6287) About Me  (Show Source):
You can put this solution on YOUR website!
You want to do the following:
60 gm. of 32% sugar solution plus x gm. of 100% sugar solution to make (60+x) gm. of 50% sugar solution. Change the percents to their decimal equivalents and write the equation.
0.32%2860%29+%2B+x+=+0.5%2860%2Bx%29 Simplify and solve for x, the number of grams of sugar to add.
19.2+%2B+x+=+30+%2B+0.5x Subtract 0.5x from both sides.
19.2+%2B+0.5x+=+30 Subtract 19.2 from both sides.
0.5x+=+10.8 Finally, divide both sides by 0.5
x+=+21.6
You will need to add 21.6 grams of sugar to the 60 grams of 32% sugar solution to make 81.6 grams of 50% sugar solution.