SOLUTION: 1. two numbers wich differ by 3, have a product of 88. Find them. 2. The orduct of two consecutive odd numbers is 143. Form an algebraic equation and solve it to find the numbe

Question 188895: 1. two numbers wich differ by 3, have a product of 88. Find them.
2. The orduct of two consecutive odd numbers is 143. Form an algebraic equation and solve it to find the numbers.
3. One number exceeds another by 7. Their product is 60. Form an quation in algebra and solve it to find the number.
4. The square of the smallest of three consecutive positive integers exceeds the sum of teh other two numbers by 45. Solve algebraically to find the numbers.
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!

1. Two numbers wich differ by 3, have a product of 88. Find them

Let x = 1st number
x-3 = 2nd number (differ by 3)
Then,

or , 1st number
or , 2nd number

Check, , good. Or , also good.

2. The product of two consecutive odd numbers is 143. Form an algebraic equation and solve it to find the numbers.

Let x= 1st odd number
x+2= 2nd odd number
Then,

or , 1st odd number
or , 2nd odd number

Check, , good. Or, , good.

3. One number exceeds another by 7. Their product is 60. Form an equation in algebra and solve it to find the number.

Let x= one number
x+7 = another number
Then,

or , one number
or , another number

Let's check, , good. Or, , good.

I'll leave the last number for you (#4) for your exercise.
Just follow thru just like the 1st 3 numbers above.

Thank you,
Jojo

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