SOLUTION: I'm stuck on this problem, the 1 part oil in the problem is giving me a problem. Mixture Problem A forester mixies gasoline and oil to make 2 gallons of mixture for his two-cyc

Question 187044This question is from textbook College Algebra A Graphing Approach
: I'm stuck on this problem, the 1 part oil in the problem is giving me a problem.
Mixture Problem
A forester mixies gasoline and oil to make 2 gallons of mixture for his two-cycle chainsaw engine. This mixture is 32 parts gasoline and 1 part oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil?
Thanks This question is from textbook College Algebra A Graphing Approach

Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!

Let x=amount of gas that needs to be added
Since we are only adding gas, the amount of oil before we add the gas (2/32) is the same as the amount of oil after we add the gas ((2+x)/40), so:
2/32=(2+x)/40=
1/16=(2+x)/40 multiply each side by 80
5=2(2+x);
5=4+2x
2x=1
x=1/2 gal-----------------amount of gas that needs to be added
CK
2/32=2.5/40
1/16=1/16
Hope this helps---ptaylor
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