SOLUTION: An 8 liter container in the lab is full of 40% acid solution. A Student working in the lab accidentally spills some of the solution and to hide his mistake he fills up the containe

Question 180961This question is from textbook College Algebra
: An 8 liter container in the lab is full of 40% acid solution. A Student working in the lab accidentally spills some of the solution and to hide his mistake he fills up the container with pure water. If the new solution is 30% acid, how much did he spill? This question is from textbook College Algebra

Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!

Let x=amount of the 40% solution that is spilled and the amount of pure water that is added back
Now we know that the amount of pure acid remaining after the spill(0.40(8-x)) has to equal the amount of pure acid that is in the final solution after the water is added(0.30*8). So our equation to solve is:
0.40(8-x)=0.30*8 get rid of parens
3.2-0.40x=2.4 subtract 3.2 from each side
3.2-3.2-0.40x=2.4-3.2 collect like terms
-0.40x=--0.8
x=2 liters------------------------amount that was spilled
CK
0.40*6=0.30*8
2.4=2.4
Hope this helps---ptaylor

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