SOLUTION: A 16-quart radiator contains a 50% solution of antifreeze. How much needs to be drained out and replaced with pure antifreeze to obtaina a 60% antifreeze solution?

Question 177529: A 16-quart radiator contains a 50% solution of antifreeze. How much needs to be drained out and replaced with pure antifreeze to obtaina a 60% antifreeze solution?
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!


amount of pure antifreeze   pure antifreeze to + pure antifreeze = pure antifre
in original solution      - be drained out       added             in final sol.
:
Let x represent the amount of antifreeze to be added
:
.5(16)-.5(x)+x=.6(16)
:
8-.5x+x=9.6
:
.5x=1.6
:
gallons of pure antifreeze

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