# SOLUTION: Chocolate coffee beans sell for \$7.00 per pound and hazelnut coffee beans sell for \$6.10 per pound. One customer wants a 6 pound mixture of both types of coffee. How many pounds of

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Chocolate coffee beans sell for \$7.00 per pound and hazelnut coffee beans sell for \$6.10 per pound. One customer wants a 6 pound mixture of both types of coffee. How many pounds of      Log On

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 Question 17727: Chocolate coffee beans sell for \$7.00 per pound and hazelnut coffee beans sell for \$6.10 per pound. One customer wants a 6 pound mixture of both types of coffee. How many pounds of each should be used if the mixture is to cost \$6.40 per pound? I have tried making tables,and writing an equation from each, but I keep getting the wrong answer and I am very confused. I need to know how to set these up to solve them, then I will be fine. It is the writing of the initial equation that I can't figure out. Thanks for your help.Answer by LilSkittleMd(119)   (Show Source): You can put this solution on YOUR website!Let c=chocolate coffee Let h=hazelnut coffee Since you need a 6 pound mixture of both coffees, you have to add them together, so your first equation will be: c+h=6 You need a 6 pound mixture that costs 6.40 per pound. For this equation you take the price per coffee multiplied by the type of coffee. And since you need a 6 pound mixture that costs 6.40 per pound, multipy 6.40 by 6 to get the total of the mixture. 7c+6.10h=38.4 From there you can solve by substitution. c=6-h 7(6-h)+6.1h=38.4 42-7h+6.1h=38.4 42-0.9h=38.4 -0.9h=-3.6 h=4 c+4=6 c=2 2 pounds of chocolate coffee should be used 4 pounds of hazelnut coffee should be used. Hope that helps.