SOLUTION: A chemist wishes to mix some pure acid with a 10% solution to obtain 60 liters of a 20% acid solution. How many liters of each of the original solutions are needed? I know

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Question 170499: A chemist wishes to mix some pure acid with a 10% solution to obtain 60 liters of a 20% acid solution. How many liters of each of the original solutions are needed?


I know I need to set up a chart and have two equations but I am really stuck on this one.
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets call amount of 10% solution x and the amount of pure acid y.
:
x+y=60..eq 1
.1x+1y=.2(60)..eq 2
:
multiply eq 2 by -1 and subtract from eq 1 to eliminate the y terms
:
.9x=48
:
highlight%28x=53.33%29 amount of 10% solution
highlight%28y=60-53.33=6.67%29amount of pure acid