SOLUTION: Tony has two kind of tea, one selling at P280 per kilogram and the other at P305 per kilogram. How many kilograms of each should she get from to make a 25-kilogram blend which will

Question 169880: Tony has two kind of tea, one selling at P280 per kilogram and the other at P305 per kilogram. How many kilograms of each should she get from to make a 25-kilogram blend which will sell at P290 per kilo?
please give me the table for your answers
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Mixture_Word_Problems/169880 (2008-11-27 06:59:42): Tony has two kind of tea, one selling at P280 per kilogram and the other at P305 per kilogram. How many kilograms of each should she get from to make a 25-kilogram blend which will sell at P290 per kilo?
.
Let x = amount of P280 per kilogram
then
25-x = amount of P305 per kilogram
.
280x + 305(25-x) = 290(25)
280x + 7625 - 305x = 7250
375 - 25x = 0
375 = 25x
15 kilograms = x (amount of P280 per kilogram)
.
amount of P305 per kilogram:
25-x = 25-15 = 10 kilograms
RELATED QUESTIONS
If a merchant has two types of tea, one work $2.70 per kilogram and the other worth $3.00 (answered by mananth)

joan bought 8 and 3/4 kilograms of ground beef at P280 per kilogram. how much did she... (answered by Theo)

A mixture of birdseed contains sunflower seeds worth $1.30 per kilogram and other seeds... (answered by ptaylor)

A dealer wishes to mix cashew nuts selling at 192 dollars per kilogram and peanuts... (answered by josgarithmetic)

1. An owner of a gourmet food store has two varities of herbal tea, one that cost costs... (answered by ankor@dixie-net.com)

Ten kilograms of mixed nuts sell for $595.00 per kilogram. The mixture is obtained from... (answered by robertb)

International coffee Grounds has two kinds of coffee. Coffee a costs $12 per kilogram,... (answered by jorel1380)

Rhona has apples that sell 80 pesos and 100 pesos per kilogram. How many kilograms of... (answered by stanbon)

Problem 1 Separate 102 into two parts such that the larger part divided by the smaller... (answered by josgarithmetic)