# SOLUTION: A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline mus

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline mus      Log On

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 Question 167370: A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline must be added to bring the mixture to 40 part gasoline and 1 part oil? I tried to make a chart to list everything I knew from the problem and see how I could solve it, but I'm not sure where to start from.Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website!Let x=amount of gas that needs to be added Now we know that the amount of oil in the 32-1 mixture is the same as the amount of oil in the 40-1 mixture (since we neither add or take away any oil); so: 2*(1/32)=1/40(2+x) get rid of parens 1/16=1/20 + x/40 (LCD=80) multiply each term by 80 5=4+2x subtract 4 from each side 5-4=2x divide by 2 x=1/2 gal amount of gas that needs to be added CK (1/32)*2=(1/40)*2.5 1/16=1/16 Hope this helps------ptaylor