SOLUTION: how many ounces of a 30% alcohol solution must be mixed with 40 ounces of an 80% alcohol solution to get a 70% solution?
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Question 160227: how many ounces of a 30% alcohol solution must be mixed with 40 ounces of an 80% alcohol solution to get a 70% solution?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
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Let x = amount of 30% alcohol added
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.30x + .80(40) = .70(40+x)
.30x + 32 = 28 + .70x
32 = 28 + .40x
4 = .40x
4/.40 = x
10 ounces = x (amount of 30% alcohol added)
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