SOLUTION: Suppose we wish to mix some 32% salt solution with some 58% salt solution to produce ten liters of 46.3% salt solution. How many liters of each of the starting solutions needs to b

Question 159494: Suppose we wish to mix some 32% salt solution with some 58% salt solution to produce ten liters of 46.3% salt solution. How many liters of each of the starting solutions needs to be used?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.58x+.32(10-x)=.463*10
.58x+3.2-.32x=4.63
.26x=4.63-3.2
.26x=1.43
x=1.43/.26
x=5.5 liters of 58% solution is used.
10-5.5=4.5 liters of 32% solution is used.
Proof:
.58*5.5+.32*4.5=.463*10
3.19+1.44=4.63
4.63=4.63
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