SOLUTION: Soybean meal is 14% protein, cornmeal is 7% protein. How many pounds of each should be mixed together to get a 280 pound mixture that is 12% protein?

Question 159214This question is from textbook
: Soybean meal is 14% protein, cornmeal is 7% protein. How many pounds of each should be mixed together to get a 280 pound mixture that is 12% protein? This question is from textbook

Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=amount of soybean meal needed
Then 280-x=amount of cornmeal needed
Now we know that the amount of pure protein in the soybean meal(0.14x) plus the amount of pure protein in the cornmeal(0.07(280-x)) has to equal the amount of pure protein in the final mixture(0.12*280). So, our equation to solve is:
0.14x+0.07(280-x)=0.12*280 get rid of parens and simplify
0.14x+19.6-0.07x=33.6 subtract 19.6 from each side
0.14x-0.07x+19.9-19.6=33.6-19.6 collect like terms
0.07x=14 divide each side by 0.07
x=200 lb-----------------------------------amount of soybean meal needed
280-x=280-200=80 lb----------------------amount of cornmeal needed
CK
200*0.14+80*0.07=280*0.12
28+5.6=33.6
33.6=33.6
Hope this helps---ptaylor

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