# SOLUTION: a contractor mixes concrete from bags of pre-mix for small jobs. How many bags with 11% cement should he mix with 10 bags of 12.5% cement to produce a mix containing 12% cement?

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 Question 159103: a contractor mixes concrete from bags of pre-mix for small jobs. How many bags with 11% cement should he mix with 10 bags of 12.5% cement to produce a mix containing 12% cement? Found 2 solutions by checkley77, nerdybill:Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!.11x+.125*10=.12(10+x) .11x+1.25=1.2+.12x .11x-.12x=1.2-1.25 -.01x=-.05 x=-.05/-.01 x=5 bags of 12% is used. Proof: .11*5+.125*10=.12(10+5) .55+1.25=.12*15 1.8=1.8 Answer by nerdybill(6960)   (Show Source): You can put this solution on YOUR website!a contractor mixes concrete from bags of pre-mix for small jobs. How many bags with 11% cement should he mix with 10 bags of 12.5% cement to produce a mix containing 12% cement? . Let x = bags of 11% cement to be added . "cement from 11%" + "cement from 12.5%" = "total cement in mix" .11x + .125(10) = .12(10+x) .11x + 1.25 = 1.2 + .12x 1.25 = 1.2 + .01x .05 = .01x 5 bags = x