SOLUTION: How many gallons of a 80% antifreeze must be mixed with 70 gallons of 25% antifreeze to get a mixture of 70% antifreeze
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Question 158857: How many gallons of a 80% antifreeze must be mixed with 70 gallons of 25% antifreeze to get a mixture of 70% antifreeze
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
How many gallons of a 80% antifreeze must be mixed with 70 gallons of 25% antifreeze to get a mixture of 70% antifreeze
.
Let x = amount of 80% antifreeze added
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"amt of antifreeze added" + "amt in antifreeze in the 70 gals" = "amt of antifreeze in final solution"
.80x + .25(70) = .70(70+x)
.80x + 17.5 = 49 + .70x
.10x + 17.5 = 49
.10x = 31.5
x = 31.5/.10
x = 315 gallons
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