# SOLUTION: A food store a 10-lb mixture of peanuts, cashews, and raisins. Peanuts cost \$1.50 per pound, cashews cost \$1.00 per pound, and raisins cost \$1.00 per pound. The mixture calls for t

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A food store a 10-lb mixture of peanuts, cashews, and raisins. Peanuts cost \$1.50 per pound, cashews cost \$1.00 per pound, and raisins cost \$1.00 per pound. The mixture calls for t      Log On

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 Question 158765: A food store a 10-lb mixture of peanuts, cashews, and raisins. Peanuts cost \$1.50 per pound, cashews cost \$1.00 per pound, and raisins cost \$1.00 per pound. The mixture calls for twice as much peanuts than cashews. The total cost of the mixture is \$12.00. How much of each ingredient did the store use?Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website! Let x=amount of peanuts and y=amount of cashews and z =amount of raisins Now we are told that: x+y+z=10--------------------------------eq1 we are also told that: 2y=x------------------------------------eq2 and (\$ are understood) 1.5x+y+z=12-----------------------------eq3 subtract eq1 from eq3 and we get 0.5x=2 divide each side by 0.5 x=4 lb----------------------------------amount of peanuts used substitute x=4 into eq2 and we get: 2y=4 divide each side by 2 y=2 lb------------------------------------------amount of cashews used substitute x=4 and y=2 into eq1 and we get 4+2+z=10 or 6+z=10 subtract 6 from each side 6-6+z=10-6 z=4 lb--------------------------------------------amount of raisins used CK 4+2+4=10 10=10 and (1.5)*4+2+4=12 6+2+4=12 12=12 Hope this helps---ptaylor