You can
put this solution on YOUR website!Let:
40% a/f =

70% a/f =

Number of gallons of

+

equals

------------------> eqn 1
We get,

----------> eqn 2
Also,

----> eqn 3
Substitute eqn 2 in eqn 3:

---->

----------------------> for the 40% a/f
In eqn 2:

----------------> for the 70% a/f
In doubt? go back eqn 3:

Thank you,
Jojo
You can
put this solution on YOUR website!A 40% antifreeze solution and a 70% antifreeze solution is mixed to make 12 gallons of 50% antifrezze solution. How many gallons of each antifreeze solution should be used.
SOLUTION:
...............GALLONS....................%..........TOTAL
70% AF......... X........................0.7.........0.7X
40% AF..........Y........................0.4.........0.4Y
MIX 50%.....X+Y=12............0.5............0.5*12=6
0.7X+0.4Y=6 EQ 1
X+Y=12 EQ 2
Solve for y and x and get the answer