SOLUTION: Pure acid is to be added to a 10% acid solution to obtain 21L of a 40% acid solution. what amount of each should be used?

SOLUTION: Pure acid is to be added to a 10% acid solution to obtain 21L of a 40% acid solution. what amount of each should be used?

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Question 157315: Pure acid is to be added to a 10% acid solution to obtain 21L of a 40% acid solution. what amount of each should be used?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x+.1(21-x)=.4*21
x+2.1-.1x=8.4
.9x=8.4-2.1
.9x=6.3
x=6.3/.9
x=7 gallons of pure acid is needed.
21-7=14 gallons of 10% acid is needed.
Proof:
7+.1*14=8.4
7+1.4=8.4
8.4=8.4

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