Question 15639: This problem has me stumped bcause I have 8 ounces already mixed and need to add to it to get 12 ounces. If I was just adding enough chocolate syrup to make it 42 percent, I would not be so confused. Here is the problem:
I want to make the perfect 12 ounce cup of chocolate milk. It requires that the mixture is 42% chocolate syrup. What I have right now is 8 ounces of milk/syrup mixture that I know contains 30% syrup. What must the syrup concentration be in the remaining mixture that I must add in order to achieve perfection? Answer by Earlsdon(6287) (Show Source):
You can put this solution on YOUR website! You'll need to set up the equation for the following:
8 oz of 30% syrup mixture + 4 oz of x% syrup mixture = 12 oz of 42% syrup mixture. Change the percents to decimals. The equation is:
Simplify and solve for x.
Subtract 2.4 from both sides.
Divide both sides by 4.
Convert to a percent.
x = 66%