SOLUTION: Tickets for a school play sold for $7.50 for each adult ticket and $3.00 each per childs ticket. The receipts for 113 tickets were$663. Find the number of adult tickets sold.
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: Tickets for a school play sold for $7.50 for each adult ticket and $3.00 each per childs ticket. The receipts for 113 tickets were$663. Find the number of adult tickets sold.
Log On
Question 155801: Tickets for a school play sold for $7.50 for each adult ticket and $3.00 each per childs ticket. The receipts for 113 tickets were$663. Find the number of adult tickets sold. Found 2 solutions by stanbon, nerdybill:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Tickets for a school play sold for $7.50 for each adult ticket and $3.00 each per childs ticket. The receipts for 113 tickets were$663. Find the number of adult tickets sold.
--------------------
Solving with one variable:
Value EQUATION: 7.5x + 3(113-x) = 663
7.5x + 339 - 3x = 663
4.5x = 324
x = 72 (number of adult tickets sold)
113-x = 113-73 = 41 (number of child tickets sold)
===================================================
Cheers,
Stan H.
You can put this solution on YOUR website! Tickets for a school play sold for $7.50 for each adult ticket and $3.00 each per childs ticket. The receipts for 113 tickets were$663. Find the number of adult tickets sold.
.
Let x = number of adult tickets sold
then because there were a total of 113 tickets sold:
113-x = number of child's tickets
.
7.50x + 3.00(113-x) = 663
7.50x + 339 - 3x = 663
4.50x + 339 = 663
4.50x = 324
x = 72 (number of adult tickets sold)