SOLUTION: Solution A is 80% Alcohol and Solution B is 50% Alcohol. How many Liters of each solutions should be mixed in order to make 100 Liters of a solution that is 68% alcohol?

Question 154328: Solution A is 80% Alcohol and Solution B is 50% Alcohol. How many Liters of each solutions should be mixed in order to make 100 Liters of a solution that is 68% alcohol?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let a="liters of Solution A" and b="liters of Solution B" __ a+b=100 __ b=100-a

(80%)a+(50%)b=(68%)100 __ .8a+.5b=68 __ substituting __ .8a+.5(100-a)=68 __ distributing __ .8a+50-.5a=68

subtracting 50 __ .3a=18 __ dividing by .3 __ a=60

substituting b=100-(60) __ b=40
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