SOLUTION: Hello, please explain to me how I should set up a system of equations to solve this problem. How many liters of a 30% acid solution must be added to a 10% acid solution to obtai

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You haven't given enough info to solve. How much 10% solution do you start with?

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We respect everybody here but there's no harm in trying this one:
Remember the following:
= liters of acid = unknown????
= liters of solution = unknown???
= final stage of acid when mixed w/ solution
Now, we all know when we add the volume of & we get 32 Liters. To show:

-----------------> eqn 1
Now, "percent of concentration" makes the difference on how many "Liters" of acid we need to put. Putting this into eqn,
------------> working eqn
In summary of the working eqn, 30% of Liters of acid + 10% of Liters of solution equals 15% of 32 Liters of the NEW acid solution.
.
In eqn 1 we get, and substitute in our working eqn:




---------------> amount of Acid Solution that must be added.
FOR THE AMOUNT of SOLUTION, go back eqn 1,
,
--------------> amount of SOLUTION that must be added.
Besides,


Thank you,
Jojo