You can
put this solution on YOUR website!a contractor has a 24-pound mixture that is no-fourth cement, and three-fourths sand. How much of a mixture that is half cement and half sand needs to be added to produce a mixture that is one-third cement?
:
We can write an equation based on the amt of cement
;
Let x = amt of half cement mixture required
:
(24) +
x =
(x+24)
Multiply equation by 12 to get rid of the denominators
:
3(24) + 6x = 4(x+24)
:
72 + 6x = 4x + 96
:
6x - 4x = 96 - 72
:
2x = 24
x =
x = 12 lb of the half cement mixture
;
:
we can check solution base on the amt of sand:
(24) +
(12) =
(12+24)
18 + 6 =
*36
