# SOLUTION: a bottle contains 750 ml of fruit punch with a concentration of 50% pure fruit juice. Jill drinks 100 ml of the punch and then refills the bottle with an equal amount of a cheaper

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 Question 149352: a bottle contains 750 ml of fruit punch with a concentration of 50% pure fruit juice. Jill drinks 100 ml of the punch and then refills the bottle with an equal amount of a cheaper brand of punch. If the concentration of juice in the bottle is now reduced to 48%, what was the concentration in the punch that jill added? and the answer is 35% but how did they got the answer?Answer by nerdybill(7090)   (Show Source): You can put this solution on YOUR website!a bottle contains 750 ml of fruit punch with a concentration of 50% pure fruit juice. Jill drinks 100 ml of the punch and then refills the bottle with an equal amount of a cheaper brand of punch. If the concentration of juice in the bottle is now reduced to 48%, what was the concentration in the punch that jill added? . Originally the bottle contained: "750 ml of fruit punch with a concentration of 50% pure fruit juice" . Then, Jill drinks 100 ml of the punch: Now, the volume is 750-100 = 650 ml The amount of fruit juice is now: .50*650 = 325 ml . Then, Jill refills (100 ml) it with a "cheaper" brand bringing the total concentration to 48% fruit juice. Let x = concentration of cheaper brand of punch then "amt of fruit juice from cheaper brand" + "amt of juice before refill" = "48% concentration" . This translates to: 100x + 325 = .48(750) 100x + 325 = 360 100x = 35 x = .35 . Therefore, the concentration was 35%