SOLUTION: I would appreciate assistance with this word problem, thanks!
A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 40%, an
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: I would appreciate assistance with this word problem, thanks!
A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 40%, and the third contains 60%. He wants to use all three solutions to obtain a mixture of 60 liters containing 50% acid, using twice as much of the 60% solution as the 40% solution. How many liters of each solution should be used.
This question is from textbook
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
2x(60%)+x(40%)+(60-3x)(20%)=60(50%) __ multiplying by 10 __ 12x+4x+120-6x=300
10x=180 __ x=18
2x=36
60-3x=6
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