SOLUTION: Soybean meal is 12% protein; cornmeal is 6% protein. How many pounds of each should be mixed together in order to get 240-lb mixture that is 9% protein? How many pounds of the co

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Question 145685: Soybean meal is 12% protein; cornmeal is 6% protein. How many pounds of each should be mixed together in order to get 240-lb mixture that is 9% protein? How many pounds of the cornmeal should be in the mixture? How many pounds of the soybean meal should be in the mixture?

Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Soybean meal is 12% protein; cornmeal is 6% protein. How many pounds of each should be mixed together in order to get 240-lb mixture that is 9% protein? How many pounds of the cornmeal should be in the mixture? How many pounds of the soybean meal should be in the mixture?
:
Since 9% is halfway between 12% and 6%, it would need 120 lb of each
:
However, here is the algebra procedure:
:
Let x = amt of soybean meal (12%)
:
It says the resulting amt = 240 lb, therefore:
(240-x) = amt of cornmeal (6%)
:
write the decimal equiv of the per cent protein equation:
.12x + .06(240-x) = .09(240)
:
.12x + 14.4 - .06x = 21.6
:
.12x - .06x = 21.6 - 14.4
:
.06x = 7.2
x =
x = 120 lb of soy meal
Then
240 - 120 = 120 lb of cornmeal

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