SOLUTION: How much pure water must be mixed with 6 pints of 90% developer to produce a mixture that is 17% developer?

Question 143892: How much pure water must be mixed with 6 pints of 90% developer to produce a mixture that is 17% developer?
Found 2 solutions by stanbon, scott8148:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How much pure water must be mixed with 6 pints of 90% developer to produce a mixture that is 17% developer?
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active ingredient + active ingredient = active ingredient
0.9*6 + 0*x = 0.17(6+x)
5.4 = 1.02 + 0.17x
4.38 = 0.17x
x = 25.76 pints ( pure water must be mixed with the 90% developer)
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Cheers,
Stan H.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let x="pints of water" __ 6(90%)+x(0%)=(6+x)(17%)

multiplying by 100 to clear percentages __ 540+0=102+17x

subtracting 102 __ 438=17x __ dividing by 17 __ 438/17=x
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