SOLUTION: A chemist is making 200 L of a solution that is 62% acid. He is mixing an 80% acid solution with a 30% acid solution. How much of the 80% acid solution will he use?

Question 135619: A chemist is making 200 L of a solution that is 62% acid. He is mixing an 80% acid solution with a 30% acid solution. How much of the 80% acid solution will he use?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A chemist is making 200 L of a solution that is 62% acid. He is mixing an 80% acid solution with a 30% acid solution. How much of the 80% acid solution will he use?
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80% solution DATA:
Amt = x liters; amount of acid is 0.8x liters
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30% solution DATA:
Amt = 12-x liters; amt of acid is 0.3(12-x) = 3.6-0.3x liters
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Misture DATA:
Amt = 12 liters; amt of acid is 0.62*12 = 7.44 liters
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EQUATION:
acid + acid = acid
0.8x + 2.6-0.3x = 7.44
0.5x = 4.84
x = 9.68 liters of 80% solution in the mixture
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Cheers,
Stan H.

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