# SOLUTION: What quantity of a 60% acid solution must be mixed with a 30% solution to produce 300mL of a 50% solution?

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 Question 135455This question is from textbook : What quantity of a 60% acid solution must be mixed with a 30% solution to produce 300mL of a 50% solution?This question is from textbook Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!.6x+.3(300-x)=.5*300 .6x+90-.3x=150 .3x=150-90 .3x=60 x=60/.3 x=200 ml of 60% is used. 300-200=100 ml of 30% is used. proof: .6*200+.3*100=150 120+30=150 150=150