# SOLUTION: How many milliliters of a 40% acid solution must be added to 150 milliliters of a 65% acid solution to obtain a 50% acid solution?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many milliliters of a 40% acid solution must be added to 150 milliliters of a 65% acid solution to obtain a 50% acid solution?       Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Mixtures Solvers Lessons Answers archive Quiz In Depth

 Question 134502: How many milliliters of a 40% acid solution must be added to 150 milliliters of a 65% acid solution to obtain a 50% acid solution? Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website!Let x=number of ml of 40% acid solution needed Now we know that the amount of pure acid in the 40% solution (0.40x) plus the amount of pure acid in the 65% solution(0.65*150) has to equal the amount of pure acid in the final mixture (0.50(150+x)). So our equation to solve is: 0.40x+0.65*150=0.50(150+x) simplify 0.40x+97.5=75-0.50x subtract 75 and also 0.40x from each side 0.40x-0.40x+97.5-75=75-75+0.50x-0.40x collect like terms 22.5=0.10x divide both sides by o.10 x=225 ml------------------amount of 40% solution needed CK 0.40*225+0.65*150=0.50(225+150) 90+97.5=187.5 187.5=187.5 Hope this helps---ptaylor