SOLUTION: b. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth.) w=Cr^-2(

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: b. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth.) w=Cr^-2(      Log On

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Question 134473: b. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth.) w=Cr^-2(r=distance)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
W=Cr%5E%28-2%29 Start with the given equation


W=C%281%2Fr%5E2%29 Rewrite r%5E%28-2%29 as 1%2Fr%5E2


W=C%2Fr%5E2 Multiply


100=C%2F3963%5E2 Plug in W=100 (this is the given weight) and r=3963 (this is the given distance from the center)


100=C%2F15705369 Square 3,963 to get 15,705,369


100%2A15705369=C Multiply both sides by 15,705,369


1570536900=C Multiply


So the constant is C=1570536900