SOLUTION: How many gallons of an 80% alcohol solution must be mixed with 30 gallons of a 22% solution to obtain a solution that is 70% alcohol?

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 Click here to see ALL problems on Mixture Word Problems Question 125288: How many gallons of an 80% alcohol solution must be mixed with 30 gallons of a 22% solution to obtain a solution that is 70% alcohol?Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!.8X+.22*30=.7(X+30) .8X+6.6=.7X+21 .8X-.7X=21-6.6 .1X=14.4 X=14.4/.1 X=144 GALLONS OF 80% SOLUTION IS REQUIRED. PROOF .8*144+.22*30=.7(144+30) 115.2+6.6=121.8 121.8=121.8