# SOLUTION: 1. Pat invested a total of \$3000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year. If the total yearly interest from this i

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: 1. Pat invested a total of \$3000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year. If the total yearly interest from this i      Log On

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 Click here to see ALL problems on Mixture Word Problems Question 124851: 1. Pat invested a total of \$3000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year. If the total yearly interest from this investment is \$256, how much did Pat invest at 10 percent and how much at 8 percent? Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!let x="amount @ 10%", so 3000-x="amount @ 8%" (.10)(x)+(.08)(3000-x)=256 __ .1x+240-.08x=256 __ .02x=16