SOLUTION: A chemist wishes to strengthen a mixture from 10% alcohol to 30% alcohol. How much pure alcohol should be added to 7 liters of the 10% mixture?

Question 124543This question is from textbook A Graphical Approach to College Algebra
: A chemist wishes to strengthen a mixture from 10% alcohol to 30% alcohol. How much pure alcohol should be added to 7 liters of the 10% mixture? This question is from textbook A Graphical Approach to College Algebra

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the required number of liters of pure alcohol to be added to the 7 liters of 10% alcohol solution to get (7+x) liters of 30% alcohol solution.
The 7 liters of 10% alcohol solution can be expressed as:
and we'll add x liters of 100% alcohol to this to get the (7+x)(0.3) liters.
So, here's the equation:
Simplify and solve for x.
Subtract 0.3x from both sides.
Now subtract 0.7 from both sides.
Finally, divide both sides by 0.7

The chemist will need to add 2 liters of pure alcohol to the 7 liters of the 10% alcohol solution to obtain 9 liters of 30% alcohol solution.
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