SOLUTION: A card company mixes two varieties of cards. Embossed cards cost $.65 each, and regular cards $.40 each. How many cards of each type should be included in an assortment of 25 cards

Question 124447: A card company mixes two varieties of cards. Embossed cards cost $.65 each, and regular cards $.40 each. How many cards of each type should be included in an assortment of 25 cards that costs $14?
Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A card company mixes two varieties of cards. Embossed cards cost $.65 each, and regular cards $.40 each. How many cards of each type should be included in an assortment of 25 cards that costs $14?
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Let "x" be the # of embossed cards: value is 0.65x dollars
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# of regular cards is "25-x" ; value is 0.40(25-x)=10-0.40x dollars
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EQUATION:
value + value = 14 dollars
0.65x + 10-0.40x = 14
0.25x = 4
x = 16 (# of embossed cards in the mix)
25-x = 9 (# of regular cards in the mix)
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Cheers,
Stan H.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.65X+.40(25-X)=14
.65X+10-.40X=14
.25X=14-10
.25X=4
X=4/.25
X=16 $.65 CARDS WERE SOLD.
25-16=9 $.40 CARDS WERE SOLD
PROOF
.65*16+9*.40=14
10.4+3.6=14
14=14
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