SOLUTION:
how many gallons of a 70% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? Use the six-step method
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Question 121526:
how many gallons of a 70% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? Use the six-step method
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.7X+.25*100=.6(100+X)
.7X+25=60+.6X
.7X-.6X=60-25
.1X=35
X=35/.1
X=350 GALLONS OF 70% ANTIFREEZE WILL BE NEEDED.
PROOF
.7*350+25=.6*450
245+25=270
270=270
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