SOLUTION: Isabel invested her savings in two investment funds. The amount she invested in Fund A was $6000 less than the amount she invested in Fund B. Fund A returned a 7% profit and Fund B
Question 1205652: Isabel invested her savings in two investment funds. The amount she invested in Fund A was $6000 less than the amount she invested in Fund B. Fund A returned a 7% profit and Fund B returned a 4% profit. How much did she invest in Fund B, if the total profit from the two funds together was $1780? Found 3 solutions by math_tutor2020, josgarithmetic, ikleyn:Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
x = amount invested in fund B
x-6000 = amount invested in fund A
0.07(x-6000) = profit from fund A
0.04x = profit from fund B
0.07(x-6000)+0.04x = total profit
0.07(x-6000)+0.04x = 1780
0.07x-420+0.04x = 1780
0.11x-420 = 1780
0.11x = 1780+420
0.11x = 2200
x = 2200/0.11
x = 20000 is the amount invested with fund B.
x-6000 = 20000-6000 = 14000 is the amount invested with fund A.
7% of A + 4% of B = 0.07*14000 + 0.04*20000 = 1780 total profit.
This confirms we have the correct answer.
FUND RATE AMT.INVT'D PROFIT
A 7% x
B 4% x+6000
SUM 1780
x assigned to amount in fund A, for sign convenience.
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---------------------Amount in fund B is 6000 dollars more, so . Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website! .
Isabel invested her savings in two investment funds. The amount she invested in Fund A was $6000 less
than the amount she invested in Fund B. Fund A returned a 7% profit and Fund B returned a 4% profit.
How much did she invest in Fund B, if the total profit from the two funds together was $1780?
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What you call " profit " in your post,
in professional language is called " interest ".