SOLUTION: A container contains 40L of wine which is 80% alcohol by volume. How much of the mixture should be removed and replaced by an equal volume of water so that the resulting solution w

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Question 1195288: A container contains 40L of wine which is 80% alcohol by volume. How much of the mixture should be removed and replaced by an equal volume of water so that the resulting solution will be 70%?
Found 4 solutions by josgarithmetic, math_tutor2020, Alan3354, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Wine is never as much as "80% alcohol" by volume nor by 'weight'.

The arithmetic you are looking for may go like this:






Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

The other tutor has the correct answer of 5 liters.

Here's how to check it:
If 5 liters are poured out, then 80% of that is pure alcohol
80% of 5 = 0.80*5 = 4
So 4 liters of pure alcohol is poured out and 1 liter is water.

The 40 L of wine drops to 40-5 = 35 L after the wine is poured, but then we replace those five liters with water to get back to 35+5 = 40 L again.

The amount of pure alcohol is not replaced. We go from 0.80*40 = 32 L to 32-4 = 28 L

Then notice that 28/40 = 0.70 = 70%

Therefore, the answer has been confirmed.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Wine is 80% alcolhol? 160 proof?
Maybe you meant 8% ?
Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.

To learn on typical percentage content of alcohol in wine, see this Internet source

https://www.masterclass.com/articles/learn-about-alcohol-content-in-wine-highest-to-lowest-abv-wines#:~:text=ABV%20is%20the%20global%20standard,with%20an%20average%20of%2018%25. 


   ABV is the global standard of measurement for alcohol content. 
   The range of ABV for unfortified wine is about 5.5% to 16%, with an average of 11.6%. 
   Fortified wines range from 15.5% to 25% ABV, with an average of 18%.



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