SOLUTION: Janet leaves home at 10:15a jogging 8mph.
Sue leaves the same home at 10:35am biking 18mph.
What time do they meet and at what mile?
solved for
their ratio of speed S4:J9
Algebra.Com
Question 1194658: Janet leaves home at 10:15a jogging 8mph.
Sue leaves the same home at 10:35am biking 18mph.
What time do they meet and at what mile?
solved for
their ratio of speed S4:J9 and distance of J9:S4
and at 10:25 Janet would have gone 2 2/3 miles.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Sue leaves 20 minutes or one-third hour after Janet. In that time, the distance between the two is .
If Janet catches up in x hours, then ;
;
For number of minutes,
and you can compute the time on the clock.
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What time met?
10:51AM
What distance when met?
18 miles per hour for 16 minutes
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