SOLUTION: If 8 percent of an 18-gallon solution is chlorine, how many gallons of water must be added to make a new solution that is 6 percent chlorine? A) 6 gallons B) 8 gallons C) 10 gall

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Question 1189616: If 8 percent of an 18-gallon solution is chlorine, how many gallons of water must be added to make a new solution that is 6 percent chlorine?
A) 6 gallons B) 8 gallons C) 10 gallons D) 12 gallons E) 18 gallons
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52796)   (Show Source): You can put this solution on YOUR website!
.
If 8 percent of an 18-gallon solution is chlorine, how many gallons of water must be added
to make a new solution that is 6 percent chlorine?
A) 6 gallons B) 8 gallons C) 10 gallons D) 12 gallons E) 18 gallons
~~~~~~~~~~~~~~ 

The amount of chlorine is the same (remains the same) in the original mixture and after diluting.


So, if W is the volume of water to add, we have this equation for the chlorine mass


    0.08*18 = 0.06*(18+W).


From this equation

    0.08*18 = 0.06*18 + 0.06*W

    0.08*18 - 0.06*18 = 0.06W

        0.02*18       = 0.06W

        W =  =  = 6  gallons.    ANSWER

Solved.



Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


8% of 18 gallons is 1.44 gallons.

When water is added, the amount of chlorine remains 1.44 gallons.

Let x be the total number of gallons in the final solution; then 6% of x is 1.44 gallons:




The amount of water added was 24-18=6 gallons.

ANSWER: 6 gallons, answer choice A
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