SOLUTION: q1) Together dien and jane eat 2/3 a pizza in 4 seconds. how long would it take each of them to eat the whole pizza alone if jane can eat a pizza 5 seconds faster than dien? and

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Question 1177753: q1) Together dien and jane eat 2/3 a pizza in 4 seconds. how long would it take each of them to eat the whole pizza alone if jane can eat a pizza 5 seconds faster than dien?
and
q2) Baba Yaga lost her broom somewhere between her hut and Bald Mountain, and wants to get it back. She calculates that with a tailwind of 2 km/ h, she can fly from her hut to Bald Mountain in 6 hours. Baba Yaga starts her trip, finds her broom 40 km before Bald Mountain, and turns around and flies home. The entire journey takes 9 hours. Find the speed Baba Yaga flies in quiet weather (with no tailwind or headwind).
Can someone explain step by step approach to solving this problem?

Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.

Together they eat 2/3 pizza in 4 seconds -----------> hence, together they eat the entire pizza in 6 seconds.


Let x be the time for Dien in seconds to eat the pizza alone.


Then the time for Jane to eat the pizza alone is (x-5) seconds.


The rate of eating is    for Dien  and    for Jane in terms of entire pizza per second.


The equation for the combined rate is


     +  = .


To solve it, multiply both sides by  6x*(x-5).   You will get then


    6*(x-5)  + 6x = x*(x-5)


Reduce to the standard quadratic equation


    x^2 - 5x - 12x + 30 = 0

    x^2 - 17x + 30 = 0


Factor left side


    (x-15)*(x-2) = 0.


The only positive root x= 15 seconds for Dien provides the positive value (x-5) = 10 seconds for Jane.


ANSWER.  15 seconds for Dien and 15-5 = 10 seconds for Jane to eat the entire pizza alone.

Solved.



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