SOLUTION: how many ounces of pure corn oil must be mixed with the 24 ounces of solution containing 90% olive oil to blend a salad dressing that is 54% olive oil
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Question 1176983: how many ounces of pure corn oil must be mixed with the 24 ounces of solution containing 90% olive oil to blend a salad dressing that is 54% olive oil
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
how many ounces of pure corn oil must be mixed with the 24 ounces of solution containing 90% olive oil to blend a salad dressing that is 54% olive oil?
:
let x = amt of corn oil required
the amount of olive oil is the same, only the percent changes
.90(24) = .54(x+24)
21.6 = .54x + 12.96
21.6 - 12.96 = .54x
8.64 = .54x
x = 8.64/.54
x = 16 oz of corn oil required
:
Check: resulting total amt: 16 + 24 = 40
.9(24) = 21.6 oz of olive oil
.54(40) = 21.6
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