Let x = the amount invested in fund B.


The partial interests are  0.1*6000 = 600 dollars for fund A and 0.03x dollars for fund B.


The total combined interest is 600 + 0.03x, and should be 0.06*(6000+x)  dollars  (desired).


It gives you this total interest equation


    600 + 0.03*x = 0.06*(6000+x)  dollars.


From the equation


    x =  = 8000 dollars.    ANSWER

    Please look into the last line in your post source code.


    It's me who added this line to your code.


    May I ask you PLEASE to provide this line (such line) at the end of each your post ?


    It serves to CLOSE  the font options  of your source code.


    Otherwise, these options extend their influence to the posts of other tutors on the same subject.


    THANK YOU.


    @ikleyn

 

Hi,

Juan invested his savings in two investment funds. 

The $6,000 that he invested in Fund A returned a 10% profit. 

The amount that he invested in Fund B returned a  3% profit.

if both funds together returned a  6% profit, 

find the amount invested in fund B?

___________

Let x be the amount invested in fund B

 .10($6000) + .03x = .06($6000+ x)= .06$($6000) + .06x

  .04($6000) = .03x

  .04($6000)/.03 = x = $8000 the amount invested in fund B

___________

Note:  Recommend doing the set-up by leaving the percentages in their 

original decimal form, prior to going to your calculator.

*Checking our work

 $600 + $240 = .06(14000) = $840 checks

Wish You the Best in your Studies.





 

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