SOLUTION: A mechanic needs an antifreeze-water mixture that 60% antifreeze to fill a radiator. The mechanic has antifreeze that is a 50% concentration and antifreeze that is 100% concentrati
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Question 1168702: A mechanic needs an antifreeze-water mixture that 60% antifreeze to fill a radiator. The mechanic has antifreeze that is a 50% concentration and antifreeze that is 100% concentration. How many liters of each concentration of antifreeze must be mixed to produce 10L of 60% antifreeze?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Target is 60% antifreeze.
60% is closer to 50% and farther from 100%.
MOST of the antifreeze should come from the lower concentration 50% antifreeze.
of the 10L is of the 50% antifreeze.
of 10L is of the 50% antifreeze.
8L of 50% and 2L of 100%.
--
If you would do the solution with algebra and hold off on all computation until the very end, you would see that same fraction (or 1 minus it).
v, how much 100%
10-v, how much 50%
----to account for pure antifreeze itself
-
------see the one-minus-the-other fraction form; depends on which antifreeze the variable is assigned.
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