SOLUTION: A chemist wants to make 42 ml of a 16% acid solution by mixing an 11% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use?

Question 1167841: A chemist wants to make 42 ml of a 16% acid solution by mixing an 11% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use?
Found 2 solutions by Boreal, josgarithmetic:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x ml of 11%
42-x ml of 18%
.11x+.18(42-x)=42*0.16=6.72 ml pure acid
.11x+7.56-.18x=6.72
-0.07x=-0.84
x=12 ml of 11%
42-x=30 ml of 18%
Also,
16% is 5/7 of the way from 11 to 18%
want 5/7 of the higher percent and 2/7 of the lower
with 42 ml, that is 30 ml of 18% and 12 ml of 12%.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
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,... to make 42 ml of a 16% acid solution by mixing an 11% acid solution and an 18% acid solution.
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to make M ml of a T% acid solution by mixing an L% acid solution and an H% acid solution.,...
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v of the H% acid
M-v of the L% acid

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