SOLUTION: Isabel invested her savings in two investment funds. The
$6000
that she invested in Fund A returned a
4%
profit. The amount that she invested in Fund B returned a
1%
pr
Algebra.Com
Question 1163062: Isabel invested her savings in two investment funds. The
$6000
that she invested in Fund A returned a
4%
profit. The amount that she invested in Fund B returned a
1%
profit. How much did she invest in Fund B, if both funds together returned a
2%
profit?
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
A formal algebraic setup for solving the problem....
x = amount at 4%
6000-x = amount at 1%
The average return on the $6000 was 2%:
Solve using basic algebra (I leave that to you)....
A quick and easy solution method, using logical reasoning and a bit of mental arithmetic....
The average return of 2% is "twice as close to 1% as it is to 4%". That means the amount invested at 1% was twice the amount invested at 4%.
ANSWER: $4000 at 1%; $2000 at 4%
CHECK:
.01(4000)+.04(2000) = 40+80 = 120
.02(6000) = 120
Or here is a variation of this easy method, thinking a bit differently....
The average return of 2% is 1/3 of the way from 1% to 4% (picture the three percentages on a number line). Therefore, 1/3 of the total was invested at 4%.
ANSWER: 1/3 of the total $6000, or $2000, at 4%; the rest at 1%.
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