SOLUTION: Isabel invested her savings in two investment funds. The
$6000 that she invested in Fund A returned a
4% profit. The amount that she invested in Fund B returned a
1% profit.
Algebra.Com
Question 1162955: Isabel invested her savings in two investment funds. The
$6000 that she invested in Fund A returned a
4% profit. The amount that she invested in Fund B returned a
1% profit. How much did she invest in Fund B, if both funds together returned a 2% profit?
Found 2 solutions by VFBundy, greenestamps:
Answer by VFBundy(438) (Show Source): You can put this solution on YOUR website!
FUND A:
Principal = 6000
Rate of profit = 0.04
Profit = 0.04 * 6000 = 240
FUND B:
Principal = p
Rate of profit = 0.01
Profit = 0.01p
= 0.02
0.02(6000 + p) = 240 + 0.01p
120 + 0.02p = 240 + 0.01p
0.01p = 120
p = 12000
FUND B:
Principal = p = $12,000
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Here is a quick and easy way to solve "mixture" problems like this without algebra, with just a bit of logical reasoning and some simple mental arithmetic.
The 2% overall return on the investments is twice as close to 1% as it is to 4%.
That means twice as much was invested in the fund that returned 1% as was invested in the fund that returned 4%.
Since $6000 was invested in the fund that returned 4%, the amount invested in the fund that returned 1% was 2 times $6000, or $12,000.
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