SOLUTION: How many liters each of a 50% acid solution and a 75% acid solution must be used to produce 60 liters of a 65% acid solution? (Round to two decimal places if necessary.)

Question 1158001: How many liters each of a 50% acid solution and a 75% acid solution must be used to produce 60 liters of a 65% acid solution? (Round to two decimal places if necessary.)
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
If you start with v for how much of 75%, and 60-v for how much 50%, you can form equation , from which you will find:

You can see in this solution formula a possible easy way to form a necessary fraction, to multiply by the mixture size of 60L.

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More generally for two-part mixture,

H, the high concentration percent
L, the low conc percent
T, target conc. percent
M, the size of result mixture
v, amount of the H material

and solving this for v will give

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

65% is 3/5 of the way from 50% to 75%.

That means 3/5 of the mixture must be the 75% acid.

3/5 of 60 liters is 36 liters.

ANSWER: 36 liters of 75% acid, 24 liters of 50% acid.

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